Study Guides/Chemistry/Oxidation Number of Cyanide (CN)
Study Guide ┬╖ Chemistry

What is the Oxidation Number of Cyanide (CN)?

In coordination chemistry and redox reactions, identifying the correct oxidation number of ligands and ions is crucial. The Cyanide ion ($CN^-$) is one of the most common polyatomic ions you will encounter in Class 11 and 12 Chemistry.

Question (Click to Flip)

What is the oxidation state of Iron in $K_4[Fe(CN)_6]$?

Answer

Let Iron be x. Potassium (K) is +1, CN is -1. Equation: 4(+1) + x + 6(-1) = 0. Solving this gives x = +2. So, Iron is in the +2 oxidation state.

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Key Facts

Cyanide is highly toxic because it binds to iron in the blood, preventing cells from using oxygen.

The carbon and nitrogen atoms in $CN^-$ are held together by a strong triple covalent bond.

Hydrogen cyanide (HCN) is a volatile and deadly gas.

1. Overall Charge of Cyanide

The Cyanide ion is a polyatomic ion with the chemical formula $CN^-$. Because it has a single negative charge, the overall oxidation number of the entire CN group is -1.

2. Individual Oxidation States

If a question asks for the specific oxidation states of the Carbon (C) and Nitrogen (N) atoms inside the cyanide ion, we must look at their electronegativity.

  • Nitrogen is more electronegative than Carbon.
  • In the $C \equiv N$ triple bond, Nitrogen pulls the shared electrons towards itself.
  • Therefore, Nitrogen (N) has an oxidation state of -3.
  • To make the total charge -1, Carbon must balance it out. Let Carbon's oxidation number be $x$. $x + (-3) = -1$ $x = +2$
  • Therefore, Carbon (C) has an oxidation state of +2 in the cyanide ion.

3. Role in Coordination Compounds

In complex coordination compounds (like Potassium ferrocyanide, $K_4[Fe(CN)_6]$), the CN group acts as a strong-field ligand. When calculating the oxidation state of the central metal atom (like Iron), you will always use -1 as the oxidation number for each CN ligand.

Questions and Answers

What is the oxidation state of Iron in $K_4[Fe(CN)_6]$?+

Let Iron be x. Potassium (K) is +1, CN is -1. Equation: 4(+1) + x + 6(-1) = 0. Solving this gives x = +2. So, Iron is in the +2 oxidation state.

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