Bromine trifluoride (BrF₃) is an interhalogen compound formed by the reaction of bromine (Br₂) and fluorine (F₂): Br₂ + 3F₂ → 2BrF₃. It is unique among solvents because it undergoes self-ionization (auto-ionization) to give BrF₂⁺ and BrF₄⁻ ions, allowing it to act as both a Lewis acid and a Lewis base. BrF₃ is a powerful fluorinating agent used in the nuclear industry.
BrF₃ is formed by: Br₂ + 3F₂ → 2BrF₃ (direct combination).
BrF₃ undergoes auto-ionization: 2BrF₃ ⇌ BrF₂⁺ + BrF₄⁻.
BrF₃ has a T-shaped molecular geometry with sp³d hybridisation.
BrF₃ acts as both a Lewis acid (donates F⁻) and Lewis base (accepts F⁻).
BrF₃ is a pale yellow liquid with a boiling point of 125.8°C.
It is used in the nuclear industry to convert UO₂ to UF₆ for uranium enrichment.
BrF₃ reacts violently with water, producing HBrO₃, HF, and Br₂.
The bond angle in BrF₃ is approximately 86°, less than 90° due to lone pair repulsion.
Bromine trifluoride is synthesised by direct combination of bromine and fluorine:
Br₂ + 3F₂ → 2BrF₃
This is a highly exothermic reaction. The reverse reaction (decomposition) can also occur: 2BrF₃ ⇌ Br₂ + 3F₂
This equilibrium lies far to the right (towards BrF₃ formation) under normal conditions because BrF₃ is thermodynamically stable. At higher temperatures, BrF₃ can decompose back to Br₂ and F₂. Fluorine's extreme electronegativity drives the forward reaction.
One of the most important properties of liquid BrF₃ is its auto-ionization (self-ionization), analogous to the self-ionization of water:
2BrF₃ ⇌ BrF₂⁺ + BrF₄⁻
In this equilibrium:
The autoionization constant at 25°C is approximately Kc ≈ 8 × 10⁻³, indicating significant self-ionization. This makes liquid BrF₃ an ionising solvent similar to water in its own chemistry.
BrF₃ acts as an amphoteric species (like water) in its own solvent system:
As a Lewis acid: BrF₃ accepts F⁻ from a donor → forms BrF₄⁻ Example: KF + BrF₃ → K⁺ + BrF₄⁻ (KF acts as F⁻ donor / base)
As a Lewis base: BrF₃ donates F⁻ to an acceptor → forms BrF₂⁺ Example: BrF₃ + SbF₅ → BrF₂⁺ + SbF₆⁻ (SbF₅ acts as F⁻ acceptor / acid)
Neutralisation in BrF₃ solvent: KBrF₄ + BrF₂·SbF₆ → KSbF₆ + 2BrF₃ This is analogous to acid-base neutralisation in water.
BrF₃ has a T-shaped molecular geometry:
BrF₃ is a polar molecule with a dipole moment, which explains its ability to act as an ionising solvent.
Physical properties:
Chemical properties:
Uses:
Bromine and fluorine react directly to form bromine trifluoride: Br₂ + 3F₂ → 2BrF₃. The reaction is exothermic. The reverse decomposition (2BrF₃ ⇌ Br₂ + 3F₂) occurs at high temperatures.
Liquid BrF₃ self-ionizes as follows: 2BrF₃ ⇌ BrF₂⁺ + BrF₄⁻. BrF₂⁺ is the fluoronium ion and BrF₄⁻ is the tetrafluorobromate ion. This makes BrF₃ an ionising solvent.
BrF₃ acts as a Lewis base by donating F⁻ to acceptors like SbF₅ (forming BrF₂⁺ + SbF₆⁻). It acts as a Lewis acid by accepting F⁻ from donors like KF (forming K⁺ + BrF₄⁻). This amphoteric behaviour is analogous to water.
BrF₃ has a T-shaped molecular geometry. The central Br atom has 3 bonding pairs and 2 lone pairs, giving a trigonal bipyramidal electron geometry and a T-shaped molecular shape, with sp³d hybridisation and F–Br–F bond angles of about 86°.
BrF₃ is primarily used in the nuclear industry for fluorinating uranium oxide (UO₂) to uranium hexafluoride (UF₆): UO₂ + 3BrF₃ → UF₆ + BrO₂F + Br₂. UF₆ is used in uranium isotope separation for nuclear fuel.
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