In CBSE Class 10 Trigonometry, you are expected to know not just the standard 0°, 30°, 45°, 60°, 90° values, but also 37° and 53° — which appear in almost every NCERT problem because they form a classic 3-4-5 right triangle.
sin 37° = 3/5 = 0.6.
cos 37° = 4/5 = 0.8.
sin 53° = 4/5 = 0.8.
cos 53° = 3/5 = 0.6.
Based on 3-4-5 Pythagorean right triangle.
37° and 53° are complementary angles (they add up to 90°). In a 3-4-5 right triangle:
| Function | Value |
|---|---|
| sin 37° | 3/5 = 0.6 |
| cos 37° | 4/5 = 0.8 |
| tan 37° | 3/4 = 0.75 |
| sin 53° | 4/5 = 0.8 |
| cos 53° | 3/5 = 0.6 |
| tan 53° | 4/3 ≈ 1.33 |
Since 37° + 53° = 90°:
sin 37° = 3/5 (based on the 3-4-5 right triangle approximation used in NCERT).
sin 53° = 4/5 = 0.8.
Because 37° and 53° are complementary angles (sum = 90°), and sin(θ) = cos(90°−θ) by definition.
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