Study Guides/Maths/Expand log₁₀(385) Using Logarithm Laws
Study Guide · Maths

Expand log₁₀(385)

To expand log₁₀(385), first factorise 385 into prime factors: 385 = 5 × 7 × 11. Then apply the product rule of logarithms: log(abc) = log a + log b + log c. So log₁₀(385) = log₁₀5 + log₁₀7 + log₁₀11.

Question (Click to Flip)

How do you expand log₁₀(385)?

Answer

Factorise 385 = 5 × 7 × 11. Apply the product rule: log₁₀(385) = log₁₀5 + log₁₀7 + log₁₀11.

Card 1 of 3 free previews

Key Facts

385 = 5 × 7 × 11 (prime factorisation).

log₁₀(385) = log₁₀5 + log₁₀7 + log₁₀11 ≈ 2.5855.

Product rule: log(ab) = log a + log b.

Quotient rule: log(a/b) = log a − log b.

Power rule: log(aⁿ) = n log a.

Expansion of log₁₀(385)

Step 1: Factorise 385. 385 ÷ 5 = 77 77 ÷ 7 = 11 11 is prime.

So 385 = 5 × 7 × 11

Step 2: Apply the product rule. log(abc) = log a + log b + log c

log₁₀(385) = log₁₀(5 × 7 × 11) = log₁₀5 + log₁₀7 + log₁₀11

Numerical check: log₁₀5 ≈ 0.6990 log₁₀7 ≈ 0.8451 log₁₀11 ≈ 1.0414 Sum ≈ 2.5855

Verification: log₁₀(385) ≈ 2.5855 ✓

Laws of Logarithms

Product rule (used above): log(ab) = log a + log b

Quotient rule: log(a/b) = log a − log b

Power rule: log(aⁿ) = n log a

Change of base: logₐ(b) = log(b)/log(a)

Special values: log₁₀(1) = 0 log₁₀(10) = 1 log₁₀(100) = 2 log₁₀(1000) = 3 ln(e) = 1

More examples using product rule: • log(6) = log(2×3) = log 2 + log 3 • log(12) = log(4×3) = log 4 + log 3 = 2log 2 + log 3 • log(100) = log(10²) = 2 log 10 = 2×1 = 2

More Expansion Examples

Example 1: Expand log(72) 72 = 8 × 9 = 2³ × 3² log 72 = log(2³ × 3²) = 3 log 2 + 2 log 3

Example 2: Expand log(a²b/c) = log a² + log b − log c = 2 log a + log b − log c

Example 3: Expand log(√5) = log(5^(1/2)) = (1/2) log 5

Example 4: Expand log(2 × 3 × 5) = log 2 + log 3 + log 5

Key approach:

  1. Factorise the number/expression.
  2. Apply product rule: log(ab) = log a + log b.
  3. Apply power rule: log(aⁿ) = n log a.
  4. Apply quotient rule for fractions: log(a/b) = log a − log b.

Questions and Answers

How do you expand log₁₀(385)?+

Factorise 385 = 5 × 7 × 11. Apply the product rule: log₁₀(385) = log₁₀5 + log₁₀7 + log₁₀11.

What is the prime factorisation of 385?+

385 = 5 × 7 × 11.

State the product rule of logarithms.+

log(ab) = log a + log b. It converts multiplication inside the log into addition of separate logs.

What is the numerical value of log₁₀(385)?+

log₁₀(385) ≈ 2.5855. (log5 + log7 + log11 ≈ 0.699 + 0.845 + 1.041 = 2.585)

More in Maths

Study Smarter with Shinyu.ai

Turn this guide into revision flashcards, a practice exam, or an AI-generated podcast — free, no signup required.