The Total Surface Area (TSA) of a cone = πr(l + r), where r is the base radius and l is the slant height. The TSA includes the curved lateral surface (πrl) and the circular base (πr²). The slant height l = √(r² + h²) where h is the perpendicular height. This is covered in NCERT Class 9 Maths, Chapter 13.
TSA of cone = πr(l + r), where r = radius and l = slant height.
Curved Surface Area (CSA) = πrl.
Base area = πr²; TSA = CSA + Base = πrl + πr².
Slant height: l = √(r² + h²).
Volume of cone = (1/3)πr²h.
NCERT Class 9 Maths Chapter 13 — Surface Areas and Volumes.
Cone — Key Terms: • r = radius of circular base • h = perpendicular height (height from base to apex) • l = slant height (distance from apex to edge of base along the surface) • Relation: l² = r² + h² → l = √(r² + h²)
Formulae: • Curved Surface Area (CSA) / Lateral Surface Area (LSA) = πrl • Area of circular base = πr² • Total Surface Area (TSA) = CSA + Base Area TSA = πrl + πr² TSA = πr(l + r)
• Volume of cone = (1/3)πr²h
Derivation of CSA = πrl: • Unroll the curved surface of the cone → it forms a sector of a circle • Radius of sector = l (slant height); Arc length of sector = 2πr (circumference of base) • Area of sector = (1/2) × arc length × radius = (1/2) × 2πr × l = πrl
Solved Examples:
Example 1: Find TSA of a cone with r = 7 cm, l = 14 cm. CSA = πrl = (22/7) × 7 × 14 = 308 cm² Base = πr² = (22/7) × 49 = 154 cm² TSA = 308 + 154 = 462 cm²
Example 2: Find TSA of cone with r = 3 cm, h = 4 cm. l = √(r² + h²) = √(9 + 16) = √25 = 5 cm TSA = πr(l + r) = π × 3 × (5 + 3) = 24π = 75.43 cm²
Example 3: Find CSA of cone with r = 5 cm, l = 13 cm. CSA = πrl = π × 5 × 13 = 65π ≈ 204.2 cm²
Summary Table:
| Formula | Expression |
|---|---|
| Slant height | l = √(r² + h²) |
| CSA (Lateral SA) | πrl |
| Base Area | πr² |
| TSA | πr(l + r) |
| Volume | (1/3)πr²h |
NCERT: Class 9 Maths Chapter 13 — Surface Areas and Volumes Value of π = 3.14159... or 22/7 (approx.)
Total Surface Area (TSA) of a cone = πr(l + r), where r = base radius and l = slant height. It equals Curved Surface Area (πrl) + Base Area (πr²). Slant height l = √(r² + h²). Example: cone with r = 7 cm, l = 14 cm → TSA = (22/7) × 7 × (14+7) = 462 cm². Volume of cone = (1/3)πr²h.
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