Study Guides/Maths/Derivative of e^2x
Study Guide Ā· Maths

What is the Derivative of $e^{2x}$?

In calculus, the exponential function $e^x$ is unique because its derivative is exactly itself ($e^x$). However, when the exponent is modified to something like $2x$, you must apply the Chain Rule to find the correct derivative.

Question (Click to Flip)

What is the derivative of e^(-x)?

Answer

Using the same chain rule, the derivative of the inner function (-x) is -1. So, the final derivative is -1 Ā· e^(-x) or -e^(-x).

Card 1 of 1 free previews

Key Facts

The number $e$ is Euler's Number, an irrational mathematical constant approximately equal to 2.71828.

The integration (anti-derivative) of $e^{2x}$ does the exact opposite. Instead of multiplying by 2, you divide: $\int e^{2x} dx = \frac{e^{2x}}{2} + C$.

1. The Answer

The derivative of $e^{2x}$ with respect to $x$ is $2e^{2x}$.

Mathematically: $\frac{d}{dx}(e^{2x}) = 2e^{2x}$

2. Step-by-Step Derivation using the Chain Rule

The Chain Rule states that the derivative of a composite function $f(g(x))$ is $f'(g(x)) \cdot g'(x)$.

  • Let our outer function be the exponential: $f(u) = e^u$
  • Let our inner function be the exponent: $u = 2x$

Step 1: Differentiate the outer function The derivative of $e^u$ is simply $e^u$. So, the first part is $e^{2x}$.

Step 2: Differentiate the inner function The derivative of $2x$ with respect to $x$ is just the constant $2$. So, $\frac{du}{dx} = 2$.

Step 3: Multiply them together According to the chain rule, we multiply the result of Step 1 by the result of Step 2. $= e^{2x} \cdot 2$ $= 2e^{2x}$

3. The General Rule

You can memorize a shortcut rule for any exponential function with a constant multiplier in the power: $\frac{d}{dx}(e^{kx}) = k \cdot e^{kx}$ (Where $k$ is any constant number. So if it was $e^{5x}$, the answer is simply $5e^{5x}$).

Questions and Answers

What is the derivative of e^(-x)?+

Using the same chain rule, the derivative of the inner function (-x) is -1. So, the final derivative is -1 Ā· e^(-x) or -e^(-x).

More in Maths

Study Smarter with Shinyu.ai

Turn this guide into revision flashcards, a practice exam, or an AI-generated podcast — free, no signup required.