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After 15 Years Mary's Age will be Four Times her Present Age

Age-related word problems are very common in algebra, particularly in linear equations in one variable for Class 8 mathematics. Let's solve the classic problem: 'Fifteen years from now, Mary's age will be four times her present age. What is Mary's present age?'

Question (Click to Flip)

What is linear equation in one variable?

Answer

A linear equation in one variable is an equation that can be written in the form ax + b = 0, where a and b are real numbers and x is a single variable.

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Key Facts

This problem tests the ability to convert English statements into algebraic equations.

Always check the answer: If she is 5 now, in 15 years she will be 20. And 20 is exactly four times 5. The answer is verified.

Step 1: Setting up the variables

Let Mary's present age be denoted by the variable $x$.

  • Present Age: $x$ years.
  • Age after 15 years: Her age will be $(x + 15)$ years.

Step 2: Framing the equation

The problem states that after 15 years, her age will be four times her present age. So, we can write the equation as: $x + 15 = 4x$

Step 3: Solving the equation

  • Subtract $x$ from both sides: $15 = 4x - x$
  • $15 = 3x$
  • Divide by 3: $x = 15 / 3$
  • $x = 5$

Therefore, Mary's present age is 5 years.

Questions and Answers

What is linear equation in one variable?+

A linear equation in one variable is an equation that can be written in the form ax + b = 0, where a and b are real numbers and x is a single variable.

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