⁹C₄ = 126. This is calculated using the combinations formula: ⁿCᵣ = n! / (r! × (n−r)!)
Pascal's Triangle contains all combination values! The rth element in the nth row of Pascal's Triangle equals ⁿCᵣ. The sum of the nth row = 2ⁿ (total subsets).
Combinations Formula: ⁿCᵣ = n! / [r! × (n−r)!]
For ⁹C₄:
Numerator: 9 × 8 × 7 × 6 = 3024 Denominator: 4! = 4 × 3 × 2 × 1 = 24
3024 ÷ 24 = 126
⁹C₄ = 126
Verification using symmetry: ⁹C₄ = ⁹C₅ (since 9−4=5) ⁹C₅ = 9!/(5!×4!) = same calculation = 126 ✓
⁹C₄ represents the number of ways to choose 4 items from 9 distinct items where order does NOT matter.
Example: From a class of 9 students, how many ways can you select a committee of 4? Answer: ⁹C₄ = 126 ways
Key difference:
⁹P₄ = 9!/(9-4)! = 9!/5! = 9×8×7×6 = **3,024**. This is 4! times ⁹C₄: 24 × 126 = 3024 ✓
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