Study Guides/Physics/A Planet Moving Around a Star — Kepler's Laws and Orbital Mechanics
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Consider a Planet Moving Around a Star — Orbital Mechanics and Kepler's Laws

When a planet moves around a star, the gravitational force between them provides the centripetal force necessary for the orbital motion. The planet's orbit follows Kepler's three laws of planetary motion. For a circular orbit of radius R, the orbital speed is v = √(GM/R) and the time period is T = 2π√(R³/GM), where M is the mass of the star and G is the gravitational constant.

Question (Click to Flip)

What force keeps a planet in orbit around a star?

Answer

Gravitational force between the planet and the star provides the centripetal force required for orbital motion. For a circular orbit: GMm/R² = mv²/R, where G is the gravitational constant, M is the star's mass, m is the planet's mass, and R is the orbital radius.

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Key Facts

Gravitational force provides centripetal force for planetary orbit: GMm/R² = mv²/R.

Orbital speed: v = √(GM/R) — independent of the planet's mass.

Orbital period: T = 2π√(R³/GM).

Kepler's Third Law: T² ∝ R³.

Total energy of orbiting planet: E = −GMm/(2R) (negative = bound system).

Kepler's Second Law: equal areas swept in equal times (conservation of angular momentum).

All planets orbit in ellipses with the star at one focus (Kepler's First Law).

Kepler's Three Laws of Planetary Motion

  1. Kepler's First Law (Law of Orbits): All planets move in elliptical orbits with the star at one focus.

  2. Kepler's Second Law (Law of Areas): A line joining the planet to the star sweeps out equal areas in equal times.

    • Planet moves faster when closer to the star (perihelion).
    • Planet moves slower when farther from the star (aphelion).
    • This is a consequence of conservation of angular momentum.
  3. Kepler's Third Law (Law of Periods): T² ∝ R³ (for circular orbits, R is the radius; for elliptical, R is the semi-major axis) T²/R³ = 4π²/(GM) = constant for all planets orbiting the same star

Where:

  • T = orbital period
  • R = mean orbital radius
  • G = 6.674 × 10⁻¹¹ N·m²/kg²
  • M = mass of the star

Gravitational Force and Orbital Speed

For a circular orbit:

Gravitational force = Centripetal force GMm/R² = mv²/R

Solving for orbital speed: v = √(GM/R)

Note: Orbital speed is independent of the planet's mass!

Orbital time period: T = 2πR/v = 2πR/√(GM/R) = 2π√(R³/GM)

Squaring: T² = 4π²R³/(GM) This confirms T² ∝ R³ (Kepler's Third Law)

For Earth orbiting the Sun:

  • G = 6.674 × 10⁻¹¹ N·m²/kg²
  • M_Sun = 2 × 10³⁰ kg
  • R_Earth = 1.5 × 10¹¹ m
  • T_Earth = 365.25 days ≈ 3.156 × 10⁷ s

Energy of a Planet in Orbit

For a planet of mass m in circular orbit of radius R around a star of mass M:

Kinetic Energy: KE = ½mv² = GMm/(2R) Potential Energy: PE = −GMm/R (negative, bound system) Total Mechanical Energy: E = KE + PE = GMm/(2R) − GMm/R = −GMm/(2R)

Key observations:

  1. Total energy is NEGATIVE → planet is gravitationally bound to the star.
  2. |Total energy| = KE (magnitude of total energy equals kinetic energy).
  3. As orbit radius R increases, total energy increases (becomes less negative).
  4. To move a planet to a larger orbit, energy must be added.

Escape velocity: v_esc = √(2GM/R) = √2 × v_orbital

Questions and Answers

What force keeps a planet in orbit around a star?+

Gravitational force between the planet and the star provides the centripetal force required for orbital motion. For a circular orbit: GMm/R² = mv²/R, where G is the gravitational constant, M is the star's mass, m is the planet's mass, and R is the orbital radius.

What is the orbital speed of a planet around a star?+

The orbital speed of a planet in a circular orbit is v = √(GM/R), where G = 6.674 × 10⁻¹¹ N·m²/kg², M = mass of the star, and R = orbital radius. Note that orbital speed is independent of the planet's own mass.

State Kepler's three laws of planetary motion.+

1st Law (Orbits): Planets move in elliptical orbits with the star at one focus. 2nd Law (Areas): The line joining planet to star sweeps equal areas in equal times. 3rd Law (Periods): The square of the orbital period is proportional to the cube of the semi-major axis: T² ∝ R³.

What is the total energy of a planet orbiting a star?+

The total mechanical energy of a planet of mass m in a circular orbit of radius R is E = −GMm/(2R). The energy is negative, indicating the planet is gravitationally bound. KE = GMm/(2R) and PE = −GMm/R.

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