Study Guides/Physics/Calculate Heat Supplied in Complete Cycle — Thermodynamics First Law
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Calculate the Heat Supplied for a Complete Cycle — Thermodynamics

For a complete thermodynamic cycle, the internal energy change is zero (ΔU = 0) because the system returns to its initial state. By the first law of thermodynamics, the net heat supplied equals the net work done by the system: Q_net = W_net. The net work done in a cycle equals the area enclosed by the P-V diagram.

Question (Click to Flip)

How do you calculate the heat supplied in a complete thermodynamic cycle?

Answer

For a complete cycle, ΔU = 0, so by the first law (Q = ΔU + W), the net heat supplied equals the net work done: Q_net = W_net. The net work equals the area enclosed by the cycle on the P-V diagram.

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Key Facts

For a complete thermodynamic cycle, ΔU = 0 (internal energy returns to initial value).

By the first law: Q_net = W_net for a complete cycle.

Net work done = area enclosed by the P-V diagram loop.

Clockwise cycle on P-V diagram → positive net work (heat engine).

Anticlockwise cycle on P-V diagram → negative net work (refrigerator/heat pump).

Heat supplied (Q_absorbed) = W_net + Q_rejected.

Thermal efficiency = W_net / Q_absorbed.

First Law of Thermodynamics Applied to a Complete Cycle

First Law: ΔU = Q − W (or Q = ΔU + W)

For a complete cycle:

  • The system returns to its initial state
  • Therefore, ΔU (change in internal energy) = 0

Applying the first law: 0 = Q_net − W_net Q_net = W_net

This means:

  • Net heat absorbed by the system = Net work done by the system
  • If the cycle is clockwise on a P-V diagram → net work done is POSITIVE → heat is absorbed
  • If the cycle is anticlockwise on a P-V diagram → net work done is NEGATIVE → heat is rejected

Conclusion: To find the total heat supplied in a complete cycle, calculate the area enclosed by the cycle on the P-V diagram.

Calculating Work Done from a P-V Diagram

Work done by gas during a process = Area under the P-V curve

For a complete cycle:

  • Work done during expansion (A→B, top path) = positive
  • Work done during compression (B→A, bottom path) = negative
  • Net work = Area enclosed by the cycle = Area of the loop

For a rectangular cycle (simple example): If pressure goes from P₁ to P₂ and volume goes from V₁ to V₂: W_net = (P₂ − P₁)(V₂ − V₁)

For a circular or irregular cycle: W_net = Area of the closed loop on P-V diagram

Since Q_net = W_net for a complete cycle: Heat supplied = Area of the P-V loop

Heat Supplied vs Heat Rejected in a Cycle

In a complete cycle:

  • Q_absorbed = heat absorbed during expansion/heating processes
  • Q_rejected = heat rejected during compression/cooling processes
  • Q_net = Q_absorbed − Q_rejected = W_net

For a heat engine (clockwise cycle): Efficiency η = W_net / Q_absorbed = 1 − Q_rejected/Q_absorbed

For a refrigerator (anticlockwise cycle): COP = Q_cold / W_net = Q_cold / (Q_hot − Q_cold)

Important: 'Heat supplied' usually refers to Q_absorbed (heat added to the system in the cycle).

Questions and Answers

How do you calculate the heat supplied in a complete thermodynamic cycle?+

For a complete cycle, ΔU = 0, so by the first law (Q = ΔU + W), the net heat supplied equals the net work done: Q_net = W_net. The net work equals the area enclosed by the cycle on the P-V diagram.

Why is ΔU = 0 for a complete thermodynamic cycle?+

Internal energy (U) is a state function — it depends only on the state of the system, not the path taken. In a complete cycle, the system returns to its initial state (same temperature, pressure, and volume), so the change in internal energy ΔU = U_final − U_initial = 0.

What does the area of the P-V diagram loop represent?+

The area enclosed by the closed loop in a P-V (pressure-volume) diagram represents the net work done by the system in one complete cycle. For a clockwise cycle, this area equals the work output (positive work done by the gas).

What is the first law of thermodynamics?+

The first law of thermodynamics states that the heat added to a system equals the increase in internal energy plus the work done by the system: Q = ΔU + W. It is the law of conservation of energy applied to thermodynamic systems.

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