Chapter 13 of CBSE Class 10 Maths covers surface area and volume of solid shapes. The key shapes are Cube, Cuboid, Cylinder, Cone, Sphere, Hemisphere, and Frustum. For each shape, you need to know the Total Surface Area (TSA), Curved/Lateral Surface Area (CSA/LSA), and Volume formulas.
Cube TSA = 6a², Cuboid TSA = 2(lb + bh + hl), where a = side, l/b/h = length/breadth/height.
Cylinder CSA = 2πrh and TSA = 2πr(r + h). Volume = πr²h.
Cone CSA = πrl and TSA = πr(r + l), where l = √(r² + h²). Volume = (1/3)πr²h.
Sphere TSA = CSA = 4πr². Volume = (4/3)πr³.
Hemisphere CSA = 2πr², TSA = 3πr². Volume = (2/3)πr³.
Frustum CSA = π(R+r)l and Volume = (πh/3)(R²+r²+Rr), where l = √[h²+(R−r)²].
A cone's volume is exactly one-third of the cylinder with same base and height.
CUBE (side = a)
CUBOID (length = l, breadth = b, height = h)
Note: For a cube, all three dimensions are equal (l = b = h = a), so TSA = 2(a² + a² + a²) = 6a².
CYLINDER (radius = r, height = h)
CONE (radius = r, height = h, slant height = l)
Relationship: l² = r² + h² (Pythagoras theorem applied to cone)
Remember: The slant height l is the distance from the apex (tip) to the base edge along the surface, not through the interior.
SPHERE (radius = r)
Note: A sphere has no distinct CSA and TSA — both are 4πr².
HEMISPHERE (radius = r)
Explanation:
FRUSTUM (a cone with its top cut off) Given: radii R (bigger base) and r (smaller base), height h, slant height l
Explanation:
Note: When r = 0 (tip not cut), frustum becomes a full cone. When r = R, it becomes a cylinder.
| Shape | CSA / LSA | TSA | Volume |
|---|---|---|---|
| Cube (side a) | 4a² | 6a² | a³ |
| Cuboid (l,b,h) | 2h(l+b) | 2(lb+bh+hl) | lbh |
| Cylinder (r,h) | 2πrh | 2πr(r+h) | πr²h |
| Cone (r,h,l) | πrl | πr(r+l) | (1/3)πr²h |
| Sphere (r) | 4πr² | 4πr² | (4/3)πr³ |
| Hemisphere (r) | 2πr² | 3πr² | (2/3)πr³ |
| Frustum (R,r,h,l) | π(R+r)l | π[R²+r²+l(R+r)] | (πh/3)(R²+r²+Rr) |
Useful values: π ≈ 3.14159, π ≈ 22/7 (for approximate calculations)
Slant height formulas:
TSA of a cone = πr(r + l), where r is the base radius and l is the slant height. The slant height l = √(r² + h²), where h is the perpendicular height. CSA of cone = πrl.
CSA (Curved Surface Area) of a hemisphere = 2πr² — it covers only the curved dome. TSA (Total Surface Area) = 3πr² — it includes the curved surface plus the circular flat base (πr²). So TSA = CSA + πr² = 2πr² + πr² = 3πr².
Volume of frustum = (πh/3)(R² + r² + Rr), where R is the radius of the larger base, r is the radius of the smaller base, and h is the height. Slant height l = √[h² + (R − r)²].
TSA = 2(lb + bh + hl) = 2(5×4 + 4×3 + 3×5) = 2(20 + 12 + 15) = 2 × 47 = 94 cm².
Volume of hemisphere = (2/3)πr³ = half of sphere's volume. Volume of sphere = (4/3)πr³. So hemisphere volume = (1/2) × (4/3)πr³ = (2/3)πr³.
Common Number and Unit Conversions (Indian System)
Learn all important number conversions — lakh, crore, million, billion. Also understand unit conversions for length, area, time, and weight.
Formula for Number of Diagonals in a Polygon
Learn the formula for the number of diagonals in any polygon. Solve for triangle, quadrilateral, pentagon, hexagon with step-by-step examples.
Number Series Questions — Patterns and Types
Learn how to solve number series questions for school maths and competitive exams. Covers arithmetic, geometric, Fibonacci, and mixed series.
Number System — Lakh, Crore, Million Conversions
Learn key number conversions: 0.1 lakh, 1 crore zeros, 10 crore, 10 million to lakh, 100000 spelling. Complete Indian and international number system guide.
One Cent is Equal to How Many Square Feet?
How many square feet are there in one cent of land? Learn the exact conversion rate used in South Indian real estate (1 Cent = 435.6 sq ft).
Turn this guide into revision flashcards, a practice exam, or an AI-generated podcast — free, no signup required.