Chapter 13 of CBSE Class 10 Maths covers surface area and volume of solid shapes. The key shapes are Cube, Cuboid, Cylinder, Cone, Sphere, Hemisphere, and Frustum. For each shape, you need to know the Total Surface Area (TSA), Curved/Lateral Surface Area (CSA/LSA), and Volume formulas.
Cube TSA = 6a², Cuboid TSA = 2(lb + bh + hl), where a = side, l/b/h = length/breadth/height.
Cylinder CSA = 2πrh and TSA = 2πr(r + h). Volume = πr²h.
Cone CSA = πrl and TSA = πr(r + l), where l = √(r² + h²). Volume = (1/3)πr²h.
Sphere TSA = CSA = 4πr². Volume = (4/3)πr³.
Hemisphere CSA = 2πr², TSA = 3πr². Volume = (2/3)πr³.
Frustum CSA = π(R+r)l and Volume = (πh/3)(R²+r²+Rr), where l = √[h²+(R−r)²].
A cone's volume is exactly one-third of the cylinder with same base and height.
CUBE (side = a)
CUBOID (length = l, breadth = b, height = h)
Note: For a cube, all three dimensions are equal (l = b = h = a), so TSA = 2(a² + a² + a²) = 6a².
CYLINDER (radius = r, height = h)
CONE (radius = r, height = h, slant height = l)
Relationship: l² = r² + h² (Pythagoras theorem applied to cone)
Remember: The slant height l is the distance from the apex (tip) to the base edge along the surface, not through the interior.
SPHERE (radius = r)
Note: A sphere has no distinct CSA and TSA — both are 4πr².
HEMISPHERE (radius = r)
Explanation:
FRUSTUM (a cone with its top cut off) Given: radii R (bigger base) and r (smaller base), height h, slant height l
Explanation:
Note: When r = 0 (tip not cut), frustum becomes a full cone. When r = R, it becomes a cylinder.
| Shape | CSA / LSA | TSA | Volume |
|---|---|---|---|
| Cube (side a) | 4a² | 6a² | a³ |
| Cuboid (l,b,h) | 2h(l+b) | 2(lb+bh+hl) | lbh |
| Cylinder (r,h) | 2πrh | 2πr(r+h) | πr²h |
| Cone (r,h,l) | πrl | πr(r+l) | (1/3)πr²h |
| Sphere (r) | 4πr² | 4πr² | (4/3)πr³ |
| Hemisphere (r) | 2πr² | 3πr² | (2/3)πr³ |
| Frustum (R,r,h,l) | π(R+r)l | π[R²+r²+l(R+r)] | (πh/3)(R²+r²+Rr) |
Useful values: π ≈ 3.14159, π ≈ 22/7 (for approximate calculations)
Slant height formulas:
TSA of a cone = πr(r + l), where r is the base radius and l is the slant height. The slant height l = √(r² + h²), where h is the perpendicular height. CSA of cone = πrl.
CSA (Curved Surface Area) of a hemisphere = 2πr² — it covers only the curved dome. TSA (Total Surface Area) = 3πr² — it includes the curved surface plus the circular flat base (πr²). So TSA = CSA + πr² = 2πr² + πr² = 3πr².
Volume of frustum = (πh/3)(R² + r² + Rr), where R is the radius of the larger base, r is the radius of the smaller base, and h is the height. Slant height l = √[h² + (R − r)²].
TSA = 2(lb + bh + hl) = 2(5×4 + 4×3 + 3×5) = 2(20 + 12 + 15) = 2 × 47 = 94 cm².
Volume of hemisphere = (2/3)πr³ = half of sphere's volume. Volume of sphere = (4/3)πr³. So hemisphere volume = (1/2) × (4/3)πr³ = (2/3)πr³.
Find the Perfect Square Between 30 and 40
Learn how to find the perfect square between 30 and 40. Understand the simple multiplication math behind perfect squares with clear examples.
Place Value and Face Value — Definition and Difference
Place value = digit × its positional value. Face value = the digit itself. Example: in 5,472, place value of 4 = 400; face value of 4 = 4. Learn with a table.
Preeti Invested Rs 50000 at 8% — SI and CI Solved
Preeti invested Rs 50000 at 8% per annum. Find Simple Interest and Compound Interest for 1, 2, and 3 years. Step-by-step solution for Class 8 Maths.
Prime Factorization of 2907
2907 = 3² × 17 × 19. Prime factorization of 2907 step by step: 2907 ÷ 3 = 969, 969 ÷ 3 = 323, 323 ÷ 17 = 19. All prime factors explained.
Prime Factorization of 35280 — Step by Step
Prime factorization of 35280 = 2⁴ × 3² × 5 × 7². Step-by-step solution using division method with factor tree. Find LCM, HCF using prime factors.
Turn this guide into revision flashcards, a practice exam, or an AI-generated podcast — free, no signup required.