Study Guides/Maths/Derivative of sin x = cos x — First Principles Proof
Study Guide · Maths

What is the Derivative of sin x?

The derivative of sin x is cos x. This is one of the most fundamental results in calculus. Written in standard notation: d/dx(sin x) = cos x. The proof follows directly from the definition of the derivative using first principles, combined with two key trigonometric limits.

Question (Click to Flip)

What is the derivative of sin x?

Answer

The derivative of sin x is cos x. In notation: d/dx(sin x) = cos x. This is proved using first principles by applying the addition formula for sine and the standard limit lim(h→0)[sin h / h] = 1.

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Key Facts

d/dx(sin x) = cos x — the derivative of sine is cosine.

Proof uses first principles and the limit lim(h→0)[sin h / h] = 1.

d/dx(cos x) = −sin x; d/dx(tan x) = sec²x.

Derivatives of co-functions (cos, cot, cosec) all carry a negative sign.

The fourth derivative of sin x is sin x itself — the cycle repeats every 4 steps.

By chain rule: d/dx[sin(f(x))] = cos(f(x)) · f'(x).

d/dx(sin²x) = sin 2x (a useful result in integration and simplification).

Derivative of sin x — Result

d/dx(sin x) = cos x

This means: if f(x) = sin x, then f'(x) = cos x.

Key observations:

  • The derivative of sin x is cos x (a 90° phase shift).
  • The derivative of cos x is −sin x.
  • Differentiating sin x twice gives −sin x, and four times gives back sin x.
  • This cyclical pattern: sin x → cos x → −sin x → −cos x → sin x repeats every 4 derivatives.

Proof from First Principles

Using the definition of derivative: d/dx(sin x) = lim(h→0) [sin(x+h) − sin(x)] / h

Step 1: Expand sin(x+h) using the addition formula: sin(x+h) = sin x · cos h + cos x · sin h

Step 2: Substitute: = lim(h→0) [sin x · cos h + cos x · sin h − sin x] / h = lim(h→0) [sin x(cos h − 1) + cos x · sin h] / h

Step 3: Split the limit: = sin x · lim(h→0) [(cos h − 1)/h] + cos x · lim(h→0) [sin h / h]

Step 4: Apply the two standard limits:

  • lim(h→0) [sin h / h] = 1 (fundamental trigonometric limit)
  • lim(h→0) [(cos h − 1)/h] = 0 (derived from the first limit)

Step 5: Substitute: = sin x · 0 + cos x · 1 = cos x

Therefore, d/dx(sin x) = cos x. Q.E.D.

Derivatives of All Trigonometric Functions

All six standard trigonometric derivatives:

  1. d/dx(sin x) = cos x
  2. d/dx(cos x) = −sin x
  3. d/dx(tan x) = sec²x
  4. d/dx(cot x) = −cosec²x
  5. d/dx(sec x) = sec x · tan x
  6. d/dx(cosec x) = −cosec x · cot x

Memory tip:

  • The derivatives of 'co-' functions (cos, cot, cosec) all have a negative sign.
  • sin ↔ cos (swap and negate the derivative of cosine)
  • tan ↔ sec² (square the secant)
  • cot ↔ −cosec² (square the cosecant, negate)

Chain Rule with sin x

When sin is applied to a function of x, use the chain rule: d/dx[sin(f(x))] = cos(f(x)) · f'(x)

Examples:

  1. d/dx(sin 2x) = cos 2x · 2 = 2 cos 2x
  2. d/dx(sin x²) = cos(x²) · 2x = 2x cos(x²)
  3. d/dx(sin(3x+1)) = cos(3x+1) · 3 = 3 cos(3x+1)
  4. d/dx(sin√x) = cos√x · (1/2√x) = cos√x / (2√x)
  5. d/dx(sin²x) = 2 sin x · cos x = sin 2x [using chain rule: 2 sin x · d/dx(sin x)]

General rule: 'Differentiate the outer function, keep the inner, multiply by derivative of the inner.'

Higher Derivatives of sin x

The derivatives of sin x follow a repeating cycle of period 4:

  • 1st derivative: d/dx(sin x) = cos x
  • 2nd derivative: d²/dx²(sin x) = d/dx(cos x) = −sin x
  • 3rd derivative: d³/dx³(sin x) = d/dx(−sin x) = −cos x
  • 4th derivative: d⁴/dx⁴(sin x) = d/dx(−cos x) = sin x
  • 5th derivative: d⁵/dx⁵(sin x) = cos x (cycle repeats)

General formula for the nth derivative:

  • If n ≡ 1 (mod 4): cos x
  • If n ≡ 2 (mod 4): −sin x
  • If n ≡ 3 (mod 4): −cos x
  • If n ≡ 0 (mod 4): sin x

This cyclic property is significant in solving differential equations and Fourier analysis.

Questions and Answers

What is the derivative of sin x?+

The derivative of sin x is cos x. In notation: d/dx(sin x) = cos x. This is proved using first principles by applying the addition formula for sine and the standard limit lim(h→0)[sin h / h] = 1.

How do you prove d/dx(sin x) = cos x from first principles?+

Using the definition: d/dx(sin x) = lim(h→0)[sin(x+h)−sin x]/h. Expanding sin(x+h) = sin x cos h + cos x sin h and splitting the limit gives sin x · lim[(cos h−1)/h] + cos x · lim[sin h/h] = sin x · 0 + cos x · 1 = cos x.

What is the derivative of sin 2x?+

By the chain rule, d/dx(sin 2x) = cos 2x × 2 = 2 cos 2x.

What are the derivatives of all six trigonometric functions?+

d/dx(sin x) = cos x; d/dx(cos x) = −sin x; d/dx(tan x) = sec²x; d/dx(cot x) = −cosec²x; d/dx(sec x) = sec x tan x; d/dx(cosec x) = −cosec x cot x.

What is the second derivative of sin x?+

The second derivative of sin x is −sin x. That is, d²/dx²(sin x) = −sin x. This means sin x is a solution to the differential equation y'' + y = 0.

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