In geometry, a chord divides a circle into two regions called segments. The larger region is the Major Segment, and the smaller region is the Minor Segment. Calculating their areas is a key topic in Class 10 Mathematics.
If the chord is the exact diameter of the circle, it divides the circle into two exactly equal segments. In this special case, both the major and minor segments are called semicircles.
A segment is the region bounded by a chord and an arc of the circle.
(Don't confuse segment with sector. A sector is bounded by two radii and an arc, like a slice of pizza. A segment is bounded by a straight line chord and an arc).
There is no direct formula to find the area of the major segment. Instead, it is calculated by subtraction.
Area of Major Segment = Area of the whole Circle − Area of the Minor Segment
To break it down into steps:
Problem: A chord of a circle of radius 10 cm subtends a right angle (90°) at the center. Find the area of the major segment. (Use π = 3.14)
Step 1: Area of the whole circle Area = πr² = 3.14 × 10² = 314 cm²
Step 2: Area of the minor segment Area of Minor Sector = (θ/360) × πr² = (90/360) × 314 = ¼ × 314 = 78.5 cm² Area of Triangle = ½ × base × height = ½ × 10 × 10 = 50 cm² Area of Minor Segment = 78.5 − 50 = 28.5 cm²
Step 3: Area of the major segment Area of Major Segment = Total Area − Minor Segment = 314 − 28.5 = 285.5 cm²
The formula for the area of a sector is **(θ / 360°) × πr²**, where θ is the angle subtended by the arc at the center of the circle, and r is the radius.
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