In coordinate geometry, the angle between two intersecting straight lines can be calculated if the slopes (gradients) of the two lines are known. This is a crucial concept in Class 11 Straight Lines.
When two lines intersect, they form two pairs of angles: one acute (θ) and one obtuse (φ). Since they lie on a straight line, they are supplementary: φ = 180° − θ.
If two non-vertical lines have slopes m₁ and m₂, and θ is the acute angle between them, the formula is:
tan θ = |(m₁ − m₂) / (1 + m₁m₂)|
Where:
| | ensure the result is positive, giving the acute angle.The angle formula gives us two extremely important conditions:
1. Parallel Lines (θ = 0°) If the lines are parallel, the angle between them is 0°. Since tan 0° = 0: (m₁ − m₂) / (1 + m₁m₂) = 0 m₁ = m₂ Rule: Parallel lines have equal slopes.
2. Perpendicular Lines (θ = 90°) If the lines are perpendicular, the angle is 90°. Since tan 90° is undefined (denominator must be 0): 1 + m₁m₂ = 0 m₁m₂ = −1 Rule: The product of slopes of perpendicular lines is -1 (they are negative reciprocals).
If the lines are given as vectors in 3D space: Line 1 direction vector = a Line 2 direction vector = b
The angle θ between them is found using the dot product: cos θ = |a · b| / (|a| |b|)
Question: Find the acute angle between lines with slopes 2 and 1/3.
Solution: m₁ = 2, m₂ = 1/3
tan θ = |(m₁ − m₂) / (1 + m₁m₂)| tan θ = |(2 − 1/3) / (1 + 2(1/3))| tan θ = |(5/3) / (1 + 2/3)| tan θ = |(5/3) / (5/3)| tan θ = 1
Since tan θ = 1, the acute angle θ = 45° (or π/4 radians).
If 1 + m₁m₂ = 0, the denominator is zero, meaning tan θ is undefined. In trigonometry, tan 90° is undefined. Therefore, the angle between the lines is 90°, and the lines are exactly perpendicular.
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