In the chemical compound Calcium Fluoride (CaF₂), the valency of Fluorine (F) is 1. To understand why, we must examine the electron configurations of both Calcium and Fluorine, and how they interact to form an ionic bond. Calcium Fluoride is a classic example of how atoms transfer electrons to achieve stability.
Compound: Calcium Fluoride (CaF₂)
Nature of Bond: Ionic
Valency of Calcium in CaF₂: 2 (Donates 2 electrons)
Valency of Fluorine in CaF₂: 1 (Accepts 1 electron)
Ions Formed: One Ca²⁺ ion and two F⁻ ions.
Fluorine Group: Group 17 (Halogens)
To determine the valency of Fluorine in this specific compound, let's look at the two elements:
Because Calcium needs to lose two electrons, and a single Fluorine atom can only accept one electron, a 1:1 ratio will not work.
Instead, one Calcium atom donates its two valence electrons to two separate Fluorine atoms (one electron to each).
Because each individual Fluorine atom is only accepting exactly one electron to form the bond, the valency (combining capacity) of Fluorine in this compound is 1.
Fluorine's valency of 1 in CaF₂ is not an exception; it is the rule. As the most electronegative element on the periodic table, Fluorine virtually always exhibits a valency of 1 (an oxidation state of -1) in its compounds. It never shares its electrons to form positive oxidation states, unlike other halogens like chlorine or iodine, which can have variable valencies when bonded to oxygen.
The valency of Fluorine in Calcium Fluoride (CaF2) is 1.
Fluorine has 7 valence electrons and requires exactly 1 more electron to complete its octet. In CaF2, each fluorine atom accepts one electron from the calcium atom. Since it combines by accepting one electron, its valency is 1.
The valency of Calcium is 2, because it donates two electrons (one to each fluorine atom) to become stable.
No, Fluorine is the most electronegative element and strictly requires only one electron to complete its shell. It practically always exhibits a valency of 1 and an oxidation state of -1.
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