Study Guides/Chemistry/Relation Between Kp and Kc
Study Guide · Chemistry

Relation Between Kp and Kc in Chemical Equilibrium

In Class 11 Chemistry (Equilibrium chapter), the equilibrium constant can be expressed in terms of concentration (Kc) or partial pressure (Kp) for gaseous reactions. The mathematical relationship between them is frequently tested in exams.

Question (Click to Flip)

What happens if Δn is positive?

Answer

If Δn is positive (products have more gaseous moles than reactants), then Kp > Kc.

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Key Facts

When calculating Δn, you must strictly ignore solids and liquids. Only the moles of substances in the gaseous state (g) are counted.

The Formula

The relationship is given by the equation:

Kp = Kc(RT)^Δn

Where:

  • Kp = Equilibrium constant in terms of partial pressure
  • Kc = Equilibrium constant in terms of molar concentration
  • R = Universal Gas Constant (0.0821 L·atm/K·mol)
  • T = Absolute temperature (in Kelvin)
  • Δn = (Number of moles of gaseous products) - (Number of moles of gaseous reactants)

Derivation Concept

The derivation relies on the Ideal Gas Equation (PV = nRT). Rearranging it gives P = (n/V)RT. Since (n/V) is moles per volume, it represents molar concentration (C). Therefore, P = CRT. By substituting this partial pressure into the Kp expression, we arrive at the final formula.

When is Kp equal to Kc?

Kp is equal to Kc ONLY when Δn = 0. If the number of gaseous reactant moles equals the gaseous product moles, then Δn = 0. Since any number to the power of 0 is 1, the formula becomes Kp = Kc(1), so Kp = Kc. Example: H₂(g) + I₂(g) ⇌ 2HI(g). Here Δn = 2 - (1+1) = 0.

Questions and Answers

What happens if Δn is positive?+

If Δn is positive (products have more gaseous moles than reactants), then **Kp > Kc**.

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