Study Guides/Chemistry/Ni(CO)4 Hybridization
Study Guide · Chemistry

Hybridization of Ni(CO)₄

Ni(CO)₄ — Nickel Tetracarbonyl — is an important organometallic compound discussed in Class 12 Chemistry (Coordination Compounds and d-block elements).

Question (Click to Flip)

Why is Ni(CO)₄ sp³ and not dsp²?

Answer

Because Ni is in zero oxidation state with a full 3d¹⁰ configuration. The d orbitals are completely filled and unavailable for hybridisation. So only 4s and 4p orbitals hybridise to give sp³.

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Key Facts

Ni(CO)₄ is extremely toxic and was discovered by Ludwig Mond in 1890. The Mond process uses Ni(CO)₄ to purify nickel metal industrially.

Hybridization of Ni(CO)₄

  • Hybridization: sp³
  • Geometry/Shape: Tetrahedral
  • Bond Angle: 109.5°
  • Magnetic Nature: Diamagnetic (no unpaired electrons)

How to Determine It

Step 1: Ni in Ni(CO)₄ is in zero oxidation state (CO is a neutral ligand).

Step 2: Electronic configuration of Ni (Z=28): [Ar] 3d⁸ 4s²

Ni⁰: [Ar] 3d⁸ 4s²

Step 3: CO is a strong field ligand — it causes pairing of electrons. Under CO's influence: Ni⁰ rearranges to [Ar] 3d¹⁰ 4s⁰

Step 4: The 4s and three 4p orbitals hybridise → sp³ hybridisation

Result: 4 CO ligands occupy the 4 tetrahedral positions. All 3d electrons are now paired → diamagnetic

Comparison with [Ni(CN)4]²⁻

PropertyNi(CO)₄[Ni(CN)₄]²⁻
Oxidation state of Ni0+2
Hybridisationsp³dsp²
GeometryTetrahedralSquare planar
Magnetic natureDiamagneticDiamagnetic

Questions and Answers

Why is Ni(CO)₄ sp³ and not dsp²?+

Because Ni is in zero oxidation state with a full 3d¹⁰ configuration. The d orbitals are completely filled and unavailable for hybridisation. So only 4s and 4p orbitals hybridise to give sp³.

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