Study Guides/Chemistry/Equilibria Involving Sparingly Soluble Salts — Ksp, Common Ion Effect, Precipitation
Study Guide · Chemistry

Equilibria Involving Sparingly Soluble Salts — Ksp, Common Ion Effect Explained

When a sparingly soluble salt dissolves in water, it establishes an equilibrium between the undissolved solid and its ions in solution. This equilibrium is described by the solubility product constant (Ksp). The common ion effect reduces the solubility of a sparingly soluble salt, and precipitation occurs when the ionic product (IP) exceeds Ksp.

Question (Click to Flip)

What is the solubility product (Ksp)?

Answer

Ksp is the equilibrium constant for the dissolution of a sparingly soluble salt. For MₐXᵦ(s) ⇌ aM^(b+) + bX^(a-), Ksp = [M^(b+)]ᵃ[X^(a-)]ᵇ. It represents the maximum product of ionic concentrations in a saturated solution.

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Key Facts

Ksp (solubility product) = product of ionic concentrations raised to their stoichiometric powers.

For AgCl: Ksp = [Ag⁺][Cl⁻] = 1.8 × 10⁻¹⁰ at 25°C.

Molar solubility s of AgCl = √Ksp = √(1.8 × 10⁻¹⁰) = 1.34 × 10⁻⁵ mol/L.

Common ion effect: adding a common ion reduces the solubility of a sparingly soluble salt.

Precipitation occurs when ionic product (IP) > Ksp.

If IP < Ksp — unsaturated (no precipitation); IP = Ksp — saturated; IP > Ksp — precipitation.

Selective precipitation is used in qualitative salt analysis and water treatment.

Kidney stones (CaC₂O₄) form when the ionic product of calcium and oxalate ions exceeds Ksp.

Solubility Product (Ksp)

For a sparingly soluble salt MₐXᵦ dissolving in water: MₐXᵦ(s) ⇌ aM^(b+)(aq) + bX^(a-)(aq)

The solubility product expression: Ksp = [M^(b+)]ᵃ × [X^(a-)]ᵇ

(The solid MₐXᵦ is not included in the expression as its activity = 1)

Examples:

  1. AgCl(s) ⇌ Ag⁺ + Cl⁻ Ksp = [Ag⁺][Cl⁻] = 1.8 × 10⁻¹⁰ at 25°C

  2. BaSO₄(s) ⇌ Ba²⁺ + SO₄²⁻ Ksp = [Ba²⁺][SO₄²⁻] = 1.1 × 10⁻¹⁰

  3. Ca₃(PO₄)₂(s) ⇌ 3Ca²⁺ + 2PO₄³⁻ Ksp = [Ca²⁺]³[PO₄³⁻]²

  4. Ag₂CrO₄(s) ⇌ 2Ag⁺ + CrO₄²⁻ Ksp = [Ag⁺]²[CrO₄²⁻]

Relationship Between Ksp and Molar Solubility

Let s = molar solubility (moles of salt dissolving per litre of solution)

For AB type (1:1 salt like AgCl): [Ag⁺] = s, [Cl⁻] = s Ksp = s × s = s² s = √Ksp For AgCl: s = √(1.8 × 10⁻¹⁰) = 1.34 × 10⁻⁵ mol/L

For AB₂ type (like PbCl₂: Pb²⁺ + 2Cl⁻): [Pb²⁺] = s, [Cl⁻] = 2s Ksp = s × (2s)² = 4s³ s = (Ksp/4)^(1/3)

For A₂B type (like Ag₂CrO₄: 2Ag⁺ + CrO₄²⁻): [Ag⁺] = 2s, [CrO₄²⁻] = s Ksp = (2s)² × s = 4s³ s = (Ksp/4)^(1/3)

For A₂B₃ type (like Bi₂S₃: 2Bi³⁺ + 3S²⁻): [Bi³⁺] = 2s, [S²⁻] = 3s Ksp = (2s)²(3s)³ = 108s⁵

Common Ion Effect

The common ion effect states that the solubility of a sparingly soluble salt is reduced when a soluble salt sharing a common ion is added to the solution.

Example: Solubility of AgCl in presence of 0.1 M AgNO₃ (common ion = Ag⁺): Ksp(AgCl) = [Ag⁺][Cl⁻] = 1.8 × 10⁻¹⁰ Let s = molar solubility of AgCl in 0.1 M AgNO₃ [Ag⁺] = 0.1 + s ≈ 0.1 (since s << 0.1) [Cl⁻] = s 1.8 × 10⁻¹⁰ = 0.1 × s s = 1.8 × 10⁻⁹ mol/L

Compare: in pure water, s = 1.34 × 10⁻⁵ mol/L Solubility is reduced by a factor of ~7500!

Applications of common ion effect:

  • Qualitative analysis (selective precipitation of ions)
  • Reducing contamination in gravimetric analysis
  • Controlling precipitation in industrial processes

Ionic Product (IP) and Precipitation

The ionic product (IP) or reaction quotient Q is defined the same way as Ksp but using actual concentrations (not equilibrium concentrations):

IP = [M^(b+)]ᵃ × [X^(a-)]ᵇ (using actual concentrations)

Comparison with Ksp:

  1. IP < Ksp: Solution is unsaturated → no precipitation; more salt can dissolve
  2. IP = Ksp: Solution is saturated → at equilibrium; no net change
  3. IP > Ksp: Solution is supersaturated → precipitation occurs until IP drops to Ksp

Example: Will a precipitate form when 100 mL of 0.001 M BaCl₂ is mixed with 100 mL of 0.0004 M Na₂SO₄? Ksp(BaSO₄) = 1.1 × 10⁻¹⁰ After mixing: [Ba²⁺] = 0.001/2 = 5 × 10⁻⁴ M; [SO₄²⁻] = 0.0004/2 = 2 × 10⁻⁴ M IP = (5 × 10⁻⁴)(2 × 10⁻⁴) = 1 × 10⁻⁷ Since IP (1 × 10⁻⁷) > Ksp (1.1 × 10⁻¹⁰), BaSO₄ precipitates.

Selective Precipitation and Applications

Selective precipitation separates a mixture of ions by adjusting conditions to precipitate one ion while keeping others in solution:

Example: A solution contains Ag⁺ and Pb²⁺. Adding dilute Cl⁻:

  • Ksp(AgCl) = 1.8 × 10⁻¹⁰
  • Ksp(PbCl₂) = 1.6 × 10⁻⁵ AgCl precipitates first (lower Ksp). Pb²⁺ remains in solution.

Applications:

  1. Qualitative inorganic analysis (systematic salt analysis uses selective precipitation)
  2. Water treatment — removal of fluoride, phosphate, heavy metals
  3. Pharmaceutical manufacturing — crystallisation and purification
  4. Formation of kidney stones (CaC₂O₄, calcium oxalate) — Ksp exceeded in urine
  5. Formation of stalactites/stalagmites — CaCO₃ precipitation from Ca(HCO₃)₂ solution
  6. Antacids — Mg(OH)₂ used (low Ksp, precipitates in stomach to neutralise acid)

Questions and Answers

What is the solubility product (Ksp)?+

Ksp is the equilibrium constant for the dissolution of a sparingly soluble salt. For MₐXᵦ(s) ⇌ aM^(b+) + bX^(a-), Ksp = [M^(b+)]ᵃ[X^(a-)]ᵇ. It represents the maximum product of ionic concentrations in a saturated solution.

What is the common ion effect on solubility?+

The common ion effect states that the solubility of a sparingly soluble salt decreases when a soluble salt with a common ion is added to the solution. For example, AgCl is much less soluble in AgNO₃ solution than in pure water, because the added Ag⁺ shifts the equilibrium AgCl ⇌ Ag⁺ + Cl⁻ to the left.

When does precipitation occur in terms of Ksp and ionic product?+

Precipitation occurs when the ionic product (IP, the product of actual ion concentrations) exceeds Ksp. If IP > Ksp, the solution is supersaturated and a precipitate forms. If IP < Ksp, no precipitation occurs. If IP = Ksp, the solution is exactly saturated.

How do you calculate molar solubility from Ksp?+

Set up an ICE table with the dissolution equilibrium. For AgCl: let s = molar solubility; [Ag⁺] = s, [Cl⁻] = s; Ksp = s²; so s = √Ksp. For PbCl₂: [Pb²⁺] = s, [Cl⁻] = 2s; Ksp = 4s³; so s = (Ksp/4)^(1/3).

What is selective precipitation?+

Selective precipitation is the technique of adding a reagent to precipitate one ion while keeping others in solution, exploiting differences in Ksp values. It is used in qualitative analysis to separate and identify ions systematically.

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