Study Guides/Chemistry/Molecular Mass of Ammonium Dichromate
Study Guide · Chemistry

How to Calculate the Relative Molecular Mass of Ammonium Dichromate

Calculating the relative molecular mass (or molar mass) of a chemical compound is a fundamental skill in chemistry. To do this, you need to know the correct chemical formula of the compound and the atomic masses of its individual elements. Let's calculate it for Ammonium Dichromate.

Question (Click to Flip)

What is the difference between 'u' and 'g/mol'?

Answer

'u' (unified atomic mass unit) is used to express the mass of a single molecule. 'g/mol' is used to express the mass of one mole (Avogadro's number) of those molecules. The numerical value remains exactly the same.

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Key Facts

The relative molecular mass of Ammonium Dichromate is 252 u (or 252 g/mol).

Ammonium dichromate is an orange crystalline solid.

It is famously used in chemistry labs for the 'chemical volcano' demonstration because it decomposes violently upon heating, producing green chromium(III) oxide ash.

1. Chemical Formula

The chemical formula for Ammonium dichromate is $(NH_4)_2Cr_2O_7$.

2. Atomic Masses Required

Before we calculate, here are the approximate relative atomic masses (atomic weights) of each element involved:

  • Nitrogen (N) = 14 u
  • Hydrogen (H) = 1 u
  • Chromium (Cr) = 52 u
  • Oxygen (O) = 16 u

3. Step-by-Step Calculation

We multiply the atomic mass of each element by the number of atoms present in the formula:

  • Nitrogen (N): There are 2 Nitrogen atoms (inside the bracket multiplied by 2 outside). -> $2 \times 14 = 28$
  • Hydrogen (H): There are 8 Hydrogen atoms ($4 \times 2$). -> $8 \times 1 = 8$
  • Chromium (Cr): There are 2 Chromium atoms. -> $2 \times 52 = 104$
  • Oxygen (O): There are 7 Oxygen atoms. -> $7 \times 16 = 112$

Total Calculation: $28 + 8 + 104 + 112 = 252$

Questions and Answers

What is the difference between 'u' and 'g/mol'?+

'u' (unified atomic mass unit) is used to express the mass of a single molecule. 'g/mol' is used to express the mass of one mole (Avogadro's number) of those molecules. The numerical value remains exactly the same.

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